**NCERT Solutions For Class 10 Science Chapter 12 Electricity. Question Answer.**

Question 1.

What does an electric circuit mean?

Answer.

A continuous and closed path of an electric
current is called an electric circuit.

Question 2.

Define the unit of current.

Answer.

One ampere is the current flowing through a
circuit, when a charge of one coulomb flows through it in one second.

Question 3.

Calculate the number of electrons
constituting one coulomb of charge.

Answer.

Total charge, Q = n x e

Question 4.

Name a device that helps to maintain a
potential difference across a conductor?

Answer.

With the help of a cell or a battery.

Question 5.

What is meant by saying that potential
difference between two points is 1 volt?

Answer.

It means that 1 joule work is done in
moving 1 coulomb of positive charge from one point to the other in an elecfric
field.

Question 6.

How much energy is given to each coulomb of
charge passing through a 6 V battery?

Answer.

Potential difference (V) = 6 V

Charge (Q) = 1 coulomb

Energy = Q x V x 6 = 6 J

Question 7.

On what factors does the resistance of a
conductor depend?

Answer.

Resistance of a conductor depends on its
material, length and area of cross-section.

Question 8.

Let the resistance of an electrical
component remains constant while the potential difference across the two ends
of the component decreases to half of its former value. What change will occur
in the current through it?

Answer.

According to Ohm’s law, we have:

I ∝ V or V ∝ I

Since the potential difference (V)
decreases to half, i.e.

∴

Hence, the current flowing through the
component will become half.

Question 9.

Why are coils of electric toasters and
electric irons made of an alloy rather than a pure metal?

Answer.

This is because of the high resistivity and
high melting point of the alloy. Also, they do not oxidise when red hot.

Question 10.

Draw a schematic diagram of a circuit
consisting of a battery of three cells of 2 V each, a 5 Ω resistor, an 8 Ω
resistor, and a 12 Ω resistor, and a plug key, all connected in series.

Answer.

Question 11.

Will current flow more easily through a
thick wire or a thin wire of the same material when connected to the same
source? Why?

Answer.

The current will flow more easily through a
wire which have comparatively less resistance. According to the relation

Question 12.

Judge the equivalent resistance when the
following are connected in parallel:

(a) 1 Ω and
10
6 Ω

(b) 1 Ω and
10
3 Ω, and 10
6 Ω

Answer.

(a) Approximately but less than 1 Ω, because in a parallel combination of
resistors, the equivalent resistance is less than the least resistance.

(b) Same as
in previous part of the question.

Question 13.

Redraw the circuit of previous question
putting in an ammeter to measure the current through the resistors and a
voltmeter to measure the potential difference across the 12 Ω resistor. What
would be the readings in the ammeter and the voltmeter?

Answer.

Total resistance, Rs = 5 + 8 + 12 = 25 Ω

Question 14.

An electric lamp of resistance 100 12, a
toaster of resistance 50 11 and a water filter of resistance 500 12 are
connected in parallel to a 220 V source. What is the resistance of an electric
iron connected to the same source that takes as much current as all three
appliances, and what is the current through it?

Answer.

Given: Resistance of electric lamp, R
1 = 100Ω

Resistance of toaster, R
2 = 50Ω

Resistance of water filter, R
3 = 500Ω

Voltage, V = 220 V

Let R
p be the resistance of electric iron. Then:

Question 15.

What is
(a) the
highest,
(b) the
lowest total resistance that can be secured by combinations of four coils of
resistances 4 Ω, 8 Ω, 12 Ω, 24 Ω?

Answer.

(a) The
highest resistance can be secured by connecting all the four coils in series.

∴ Equivalent resistance of series
combination, R
s= 4 + 8 + 12+ 24 = 48 Ω

Hence, the highest
resistance that can be secured by given coils is 48 Ω.

(b) The
lowest resistance can be secured by connecting all the four coils in parallel.

∴ Equivalent resistance of parallel
combination,

or R
p = 2 Ω

Hence, the lowest resistance
that can be secured by given coils is 2 Ω.

Question 16.

Why does the cord of an electric heater not
glow while the heating element does?

Answer.

The resistance of metal used in cord has
much lower than that its element. So the heat produced by the element is much
more than that produced by the cord while passing the current.

Question 17.

Compute the heat generated while
transferring 96000 coulomb of charge in one hour through a potential
difference of 50 V.

Answer.

Given, Q = 96000 C, V= 50 volt,

t = 1 hour = 60 x 60 = 3600 s

∴ Heat generated, H = VIt

= VQ = 50 x 96000

= 4800000 = 4.8 x 10
6 J

Question 18.

An electric iron of resistance 20 12 takes
a current of 5 A. Calculate the heat developed in 30 s.

Answer.

Heat developed is equal to the work done
(W).

Given: R = 20 Ω, I = 5 A and t = 30 s

∴ W = I
2Rt = (5)
2 x 20 x 30

= 25 x 20 x 30 = 15,000 J

Hence, the heat developed by electric iron
is 15,000 J.

Question 19.

What determines the rate at which energy is
delivered by a current?

Answer.

Electric power determines the rate at which
energy is delivered by a current.

Question 20.

An electric motor takes 5 A from a 220 V
line. Determine the power of the motor and the energy consumed in 2 hr.

Answer.

Given: Current, I = 5 A, Voltage, V = 220 V
and t= 2 h

Electric power, P=VI = 220 x 5 =
1100 W

∴ Energy consumed = Pt = 1100 x 7200

= 7920000 = 792 x 10
4 J

Question 21.

What are the advantages of connecting
devices in parallel with the battery instead of connecting them in series?

Answer.

(a) When
electrical devices are connected in parallel, each is operated at the same
voltage and if one of them goes off, the others are not affected. But when
electrical devices are connected in series, this does not happen because the
circuit is broken when any one of the devices fails.

(b) In
parallel connection, the current divides itself through different devices.
This is helpful when each device has different resistance and requires
different current to operate. But in series connection this does not happen
because the same current flows through all the devices.

Question 22.

How can three resistors of resistances 2 Ω,
3 Ω and 6 Ω be connected to give a total resistance of
(a) 4 Ω and

(b) 1 Ω ?

Answer.

(a) In order
to get a resistance of 4 Ω, we can connect resistors of 3 Ω and 6 Ω in
parallel and this parallel combination in series with 2 Ω resistor.

(b) In order
to get 1 Ω resistance, we can connect all the three resistors in parallel.

Chapter End Questions

Question 1.

A piece of wire of resistance R is cut into
five equal parts. These parts are then connected in parallel. If the
equivalent resistance of this combination is R’, then the ratio

(a)

(b)

(c) 5

(d) 25

Answer.

(d) 25

Question 2.

Which of the following terms does not
represent the electrical power in a circuit?

(a) I
2R

(b) IR
2

(c) VI

(d)

Answer.

(b) IR
2

Question 3.

Two conducting wires of the same material
and of equal lengths and equal diameters are first ‘ connected in series and
then parallel in a circuit across the same potential difference. The ratio of
heat produced in series and parallel combination would be:

(a) 1 : 2

(b) 2 : 1

(c) 1 : 4

(d) 4 : 1

Answer.

(c) 1 : 4

Question 4.

An electric bulb is rated 220 V and 100 W.
When it is operated on 110 V, the )aower consumed will be

(a) 100 W ,

(b) 75 W

(c) 50 W

(d) 25 W

Answer.

(d) 25 W

Question 5.

How is a voltmeter connected in the circuit
to measure the potential difference between two points?

Answer.

A voltmeter is connected in parallel to the
circuit.

Question 6.

A copper wire has diameter 0.5 mm and
resistivity of 1.6 x 10
8 Ω m. What will be the length of this wire to make its resistance 10 Ω?
How much does the resistance change, if the diameter is doubled?

Answer.

Given: Radius, r = 0.25 mm = 0.25 x 10
-3 m

Length of the wire, l = 1

Resistance, R =10 Ω

Question 7.

The valued of current I flowing in a given
resistor for the corresponding values of potential difference V across the
resistor are given below:

I (amperes) | 0.5 | 1.0 | 2.0 | 3.0 | 4.0 |

V (volts) | 1.6 | 3.4 | 6.7 | 10.2 | 13.2 |

Plot a graph between V and I and calculate the resistance of the resistor.

Answer.

Question 8.

When a 12 V battery is connected across an
unknown resistor, there is a current of 2.5 mA in the circuit. Find the value
of the resistance of the resistor.

Answer.

Given: V= 12 volts, I = 2.5 mA = 2.5 x 10
-3 A

Resistance, R = ?

∴ Resistance =

Question 9.

A battery of 9 V is connected in series
with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much
current would flow through the 12 Ω resistor?

Answer.

Given: V= 9 volts

Applying the formula R = R
1 + R
2+ R
3+ R
4 + R
s, we get

R = 0.2 + 0.3 + 0.4 + 0.5 + 12 =
13.4 Ω

By Ohm’s law, we have

V=RI or

or 9 = 13.4 x I

or

Hence, the current flows through the 12 Ω
resistor is 0.67 A.

Question 10.

How many 176 Ω resistors (in parallel) are
required to carry 5 A on a 220 V line?

Answer.

Given: V= 220 volts, I= 5 A

Resistance of each resistor, R = 176 Ω

Number of resistors = n, We know that V = R
pI

Question 11.

Show how you would connect three resistors
each of resistance 6 ft, so that the combination has a resistance of

(a) 9 Ω, and

(b) 4 Ω. ,

Answer.

(a) In order
to get a resistance of 9 ft from the given three resistors, two resistors can
be connected in parallel and this parallel combination in series with the
third one.

(b) In order
to get a resistance of 4 ft from the given three resistors, two resistors can
be connected in series and this series in parallel with the third one.

Question 12.

Several electric bulbs designed to be used
on a 220 V electric supply line, are rated 10 W. How many lamps can be
connected in parallel with each other across the two wires of 220 V line, if
the maximum allowable current is 5 A?

Answer.

Given: Potential, V = 220 volts, P = 10 W,
I = 5 A

Let number of bulbs = n

Applying the formula P = VI, we get:

Hence, 110 bulbs can be connected is
parallel.

Question 13.

A hot plate of an electric oven connected
to a 220 volt line has two resistance coils A and B, each of 24 Ω resistance,
which may be used separately, in series, or in parallel. What are the currents
in the three cases?

Answer.

Given: Voltage, V = 220 V

Question 14.

Compare the power used in the 2 Ω resistor
in each of the following circuits:

(a) A 6 V
battery in series with 1 Ω and 2 Ω resistors, and

(b) a 4 V
battery in parallel with 12 Ω and 2 Ω resistors.

Answer.

(a) Given:
Voltage, V= 6 V

Equivalent resistance, R =
1 + 2 = 3 Ω

(b) Since the
battery is in parallel with 12 Ω and 2 Ω resistors

∴ Potential difference across 2 Ω resistor,

Question 15.

Two lamps, one rated 100 W at 220 V, and
the other 60 W at 220 V, are connected in parallel to electric mains supply.
What current is drawn from the line if the supply voltage is 220 V?

Answer.

Given: P
1 = 100 W, P
2 = 60 W and 7= 220 V

Resistance of
first lamp,

Question 16.

Which uses more energy, a 250 W TV set in 1
hr or a 1200 W toaster in 10 minutes?

Answer.

Energy used by TV set = Power x Time

Question 17.

An electric heater of resistance 8 W draws
a current of 15 A from the service mains for 2 hr. Calculate the rate at which
heat is developed in the heater.

Answer.

Given: Resistance, R = 8 Ω, t = 2 hr, I =
15 A

Rate of heat developed,

Power = I
2R = (15)
2 x 8 = 1800 W

Question 18.

Explain the following:,

(a) Why is
the tungsten used almost exclusively for filament of electric lamps?

(b) Why are
the conductors of electric heating devices such as bread toaster and electric
irons, made of an alloy rather than a pure metal?

(c) Why is
the series arrangement not used for domestic circuits?

(d) How does
the resistance of a wire vary with its area of cross-section?

(e) Why are
copper and aluminium wires usually employed for electricity transmission?

Answer.

(a) Melting
point of tungsten is very high. So it does not oxidise (burn) at high
temperatures. Secondly, the resistivity of tungsten is high. So thin wire of
tungsten which has high resistance which produces more heat enough to emit
light.

(b) This is because of the high resistivity and high melting point of the alloy. Also, they do not oxidise when red hot.

(c) Domestic circuits are not connected in series because they do not work at the same voltage and also if there is a short- circuiting in one distribution circuit, its fuse will not blow and other circuits will also be affected.

(d) Larger the area of cross-section means a large number of free electrons can move in the conductor, thereby decreasing the resistance.

(e) Copper and aluminium wires are good conductors of electricity. So they have low resistivity. They offer low opposition to the flow of current from one point to the other, hence employed for electricity.